by SubtleChromePanda2h agoETH pair0xd83237…f58fe5
∑ $n \ge 1$, $\sum_{k=1}^{n} (2k-1) = n^2$. — launched on hood.exe · rigor —/100 · ipfs://bafkreigq5zocexfzzeebwumb52xiwhl57pj24hvhc5wt7ssq4p74nofffy
Reading trades.